Halo kak, boleh minta tolong bantuin buat nyelesaiin 4 soal ini engga? dengan cara nya yaa
makasii
makasii
Materi : Bentuk Akar dan Pangkat
Soal Nomor 1
3√24 ÷ √10 × √6
= 3√24 ÷ √60
= 3√4 ÷ √10
= 3(2) ÷ √10
= 6/√10
= 6√10/(√10)²
= 6√10/10
= ⅗√10
Soal Nomor 2
12/( 4 - √10 )
= 12( 4 + √10 )/( 4 - √10 )( 4 + √10 )
= 12( 4 + √10 )( 4² - [√10]² )
= 12( 4 + √10 )( 16 - 10 )
= 12( 4 + √10 )/6
= 2( 4 + √10 )
= 8 + 2√10
Soal Nomor 3
2√10 × √40 ÷ √72
= 2√400/6√2
= 2(20)/6√2
= 20/3√2
= 20( 3√2 )/( 3√2 )²
= 20( 3√2 )/( 18 )
= 10( 3√2 )/9
= 10√2/3
= ( 10/3 )√2
Soal Nomor 4
8/( √7 + √3 )
= 8( √7 - √3 )/( √7 + √3 )( √7 - √3 )
= 8( √7 - √3 )/( [√7]² - [√3]² )
= 8( √7 - √3 )/( 7 - 3 )
= 8( √7 - √3 )/4
= 2( √7 - √3 )
= 2√7 - 2√3
Semoga bisa membantu
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[answer.2.content]
